+uint %test5a(uint %A) {
+ %B = shl uint %A, ubyte 32 ;; shift all bits out
+ ret uint %B
+}
+
+uint %test6(uint %A) {
+ %B = shl uint %A, ubyte 1 ;; convert to an mul instruction
+ %C = mul uint %B, 3
+ ret uint %C
+}
+
+int %test7(ubyte %A) {
+ %B = shr int -1, ubyte %A ;; Always equal to -1
+ ret int %B
+}
+
+ubyte %test8(ubyte %A) { ;; (A << 5) << 3 === A << 8 == 0
+ %B = shl ubyte %A, ubyte 5
+ %C = shl ubyte %B, ubyte 3
+ ret ubyte %C
+}
+
+ubyte %test9(ubyte %A) { ;; (A << 7) >> 7 === A & 1
+ %B = shl ubyte %A, ubyte 7
+ %C = shr ubyte %B, ubyte 7
+ ret ubyte %C
+}
+
+ubyte %test10(ubyte %A) { ;; (A >> 7) << 7 === A & 128
+ %B = shr ubyte %A, ubyte 7
+ %C = shl ubyte %B, ubyte 7
+ ret ubyte %C
+}
+
+ubyte %test11(ubyte %A) { ;; (A >> 3) << 4 === (A & 0x1F) << 1
+ %a = mul ubyte %A, 3
+ %B = shr ubyte %a, ubyte 3
+ %C = shl ubyte %B, ubyte 4
+ ret ubyte %C
+}
+
+int %test12(int %A) {
+ %B = shr int %A, ubyte 8 ;; (A >> 8) << 8 === A & -256
+ %C = shl int %B, ubyte 8
+ ret int %C
+}
+
+sbyte %test13(sbyte %A) { ;; (A >> 3) << 4 === (A & -8) * 2
+ %a = mul sbyte %A, 3
+ %B = shr sbyte %a, ubyte 3
+ %C = shl sbyte %B, ubyte 4
+ ret sbyte %C
+}
+
+uint %test14(uint %A) {
+ %B = shr uint %A, ubyte 4
+ %C = or uint %B, 1234
+ %D = shl uint %C, ubyte 4 ;; D = ((B | 1234) << 4) === ((B << 4)|(1234 << 4)
+ ret uint %D
+}
+uint %test14a(uint %A) {
+ %B = shl uint %A, ubyte 4
+ %C = and uint %B, 1234
+ %D = shr uint %C, ubyte 4 ;; D = ((B | 1234) << 4) === ((B << 4)|(1234 << 4)
+ ret uint %D
+}