/* x = ((*(frame + k)) & 0xf) << 2; */
ctx->seen |= SEEN_X | SEEN_DATA | SEEN_CALL;
/* the interpreter should deal with the negative K */
- if (k < 0)
+ if ((int)k < 0)
return -1;
/* offset in r1: we might have to take the slow path */
emit_mov_i(r_off, k, ctx);
#endif
if (bpf_jit_enable > 1)
- print_hex_dump(KERN_INFO, "BPF JIT code: ",
- DUMP_PREFIX_ADDRESS, 16, 4, ctx.target,
- alloc_size, false);
+ /* there are 2 passes here */
+ bpf_jit_dump(fp->len, alloc_size, 2, ctx.target);
fp->bpf_func = (void *)ctx.target;
out: