static Instruction *LowerNegateToMultiply(Instruction *Neg,
std::map<AssertingVH<>, unsigned> &ValueRankMap,
LLVMContext *Context) {
- Constant *Cst = Context->getConstantIntAllOnesValue(Neg->getType());
+ Constant *Cst = Context->getAllOnesValue(Neg->getType());
Instruction *Res = BinaryOperator::CreateMul(Neg->getOperand(1), Cst, "",Neg);
ValueRankMap.erase(Neg);
// version of the value is returned, and BI is left pointing at the instruction
// that should be processed next by the reassociation pass.
//
-static Value *NegateValue(Value *V, Instruction *BI) {
+static Value *NegateValue(LLVMContext *Context, Value *V, Instruction *BI) {
// We are trying to expose opportunity for reassociation. One of the things
// that we want to do to achieve this is to push a negation as deep into an
// expression chain as possible, to expose the add instructions. In practice,
if (Instruction *I = dyn_cast<Instruction>(V))
if (I->getOpcode() == Instruction::Add && I->hasOneUse()) {
// Push the negates through the add.
- I->setOperand(0, NegateValue(I->getOperand(0), BI));
- I->setOperand(1, NegateValue(I->getOperand(1), BI));
+ I->setOperand(0, NegateValue(Context, I->getOperand(0), BI));
+ I->setOperand(1, NegateValue(Context, I->getOperand(1), BI));
// We must move the add instruction here, because the neg instructions do
// not dominate the old add instruction in general. By moving it, we are
// Insert a 'neg' instruction that subtracts the value from zero to get the
// negation.
//
- return BinaryOperator::CreateNeg(V, V->getName() + ".neg", BI);
+ return BinaryOperator::CreateNeg(*Context, V, V->getName() + ".neg", BI);
}
/// ShouldBreakUpSubtract - Return true if we should break up this subtract of
/// X-Y into (X + -Y).
-static bool ShouldBreakUpSubtract(Instruction *Sub) {
+static bool ShouldBreakUpSubtract(LLVMContext *Context, Instruction *Sub) {
// If this is a negation, we can't split it up!
if (BinaryOperator::isNeg(Sub))
return false;
/// BreakUpSubtract - If we have (X-Y), and if either X is an add, or if this is
/// only used by an add, transform this into (X+(0-Y)) to promote better
/// reassociation.
-static Instruction *BreakUpSubtract(Instruction *Sub,
+static Instruction *BreakUpSubtract(LLVMContext *Context, Instruction *Sub,
std::map<AssertingVH<>, unsigned> &ValueRankMap) {
// Convert a subtract into an add and a neg instruction... so that sub
// instructions can be commuted with other add instructions...
// Calculate the negative value of Operand 1 of the sub instruction...
// and set it as the RHS of the add instruction we just made...
//
- Value *NegVal = NegateValue(Sub->getOperand(1), Sub);
+ Value *NegVal = NegateValue(Context, Sub->getOperand(1), Sub);
Instruction *New =
BinaryOperator::CreateAdd(Sub->getOperand(0), NegVal, "", Sub);
New->takeName(Sub);
return Context->getNullValue(X->getType());
} else if (Opcode == Instruction::Or) { // ...|X|~X = -1
++NumAnnihil;
- return Context->getConstantIntAllOnesValue(X->getType());
+ return Context->getAllOnesValue(X->getType());
}
}
}
// If this is a subtract instruction which is not already in negate form,
// see if we can convert it to X+-Y.
if (BI->getOpcode() == Instruction::Sub) {
- if (ShouldBreakUpSubtract(BI)) {
- BI = BreakUpSubtract(BI, ValueRankMap);
+ if (ShouldBreakUpSubtract(Context, BI)) {
+ BI = BreakUpSubtract(Context, BI, ValueRankMap);
MadeChange = true;
} else if (BinaryOperator::isNeg(BI)) {
// Otherwise, this is a negation. See if the operand is a multiply tree