//===----------------------------------------------------------------------===//
#include "llvm/Analysis/Dominators.h"
-#include "llvm/Support/CFG.h"
-#include "llvm/Support/Compiler.h"
-#include "llvm/Support/Debug.h"
#include "llvm/ADT/DepthFirstIterator.h"
#include "llvm/ADT/SmallPtrSet.h"
#include "llvm/ADT/SmallVector.h"
#include "llvm/Analysis/DominatorInternals.h"
#include "llvm/Assembly/Writer.h"
#include "llvm/Instructions.h"
-#include "llvm/Support/raw_ostream.h"
+#include "llvm/Support/CFG.h"
#include "llvm/Support/CommandLine.h"
+#include "llvm/Support/Compiler.h"
+#include "llvm/Support/Debug.h"
+#include "llvm/Support/raw_ostream.h"
#include <algorithm>
using namespace llvm;
bool DominatorTree::dominates(const BasicBlockEdge &BBE,
const BasicBlock *UseBB) const {
+ // Assert that we have a single edge. We could handle them by simply
+ // returning false, but since isSingleEdge is linear on the number of
+ // edges, the callers can normally handle them more efficiently.
+ assert(BBE.isSingleEdge());
+
// If the BB the edge ends in doesn't dominate the use BB, then the
// edge also doesn't.
const BasicBlock *Start = BBE.getStart();
bool DominatorTree::dominates(const BasicBlockEdge &BBE,
const Use &U) const {
+ // Assert that we have a single edge. We could handle them by simply
+ // returning false, but since isSingleEdge is linear on the number of
+ // edges, the callers can normally handle them more efficiently.
+ assert(BBE.isSingleEdge());
+
Instruction *UserInst = cast<Instruction>(U.getUser());
// A PHI in the end of the edge is dominated by it.
PHINode *PN = dyn_cast<PHINode>(UserInst);