m68k: remove redundant display of free swap space in show_mem()
authorJohannes Weiner <hannes@saeurebad.de>
Mon, 28 Apr 2008 09:13:48 +0000 (02:13 -0700)
committerLinus Torvalds <torvalds@linux-foundation.org>
Mon, 28 Apr 2008 15:58:27 +0000 (08:58 -0700)
show_mem() has no need to print the amount of free swap space manually because
show_free_areas() does this already and is called by the former.

The two outputs only differ in text formatting:

  printk("Free swap  = %lukB\n", ...);
  printk("Free swap:       %6ldkB\n", ...);

Signed-off-by: Johannes Weiner <hannes@saeurebad.de>
Cc: Geert Uytterhoeven <geert@linux-m68k.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
arch/m68k/mm/init.c

index f42caa79e4e89f9fadf73041d33ab81077e7d11f..a2bb01f5964230dccb312006a2832f5f4fac8f53 100644 (file)
@@ -79,7 +79,6 @@ void show_mem(void)
 
        printk("\nMem-info:\n");
        show_free_areas();
-       printk("Free swap:       %6ldkB\n", nr_swap_pages<<(PAGE_SHIFT-10));
        for_each_online_pgdat(pgdat) {
                for (i = 0; i < pgdat->node_spanned_pages; i++) {
                        struct page *page = pgdat->node_mem_map + i;