x86: explicitly use edx in const delay function.
authorGlauber Costa <gcosta@redhat.com>
Tue, 24 Jun 2008 13:21:25 +0000 (10:21 -0300)
committerIngo Molnar <mingo@elte.hu>
Wed, 9 Jul 2008 06:52:04 +0000 (08:52 +0200)
For x86_64, we can't just use %0, as it would
generate a mul against rdx, which is not really what we
want (note the ">> 32" in x86_64 version).

Using a u64 variable with a shift in i386 generates bad code,
so the solution is to explicitly use %%edx in inline assembly
for both.

Signed-off-by: Glauber Costa <gcosta@redhat.com>
Signed-off-by: H. Peter Anvin <hpa@zytor.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
arch/x86/lib/delay_32.c
arch/x86/lib/delay_64.c

index bf6de05445ba4cc03c3e724e144ca1ffb450b1f8..0b659a320b1ec225dcbc7cee1a3e08f9520dda8a 100644 (file)
@@ -114,7 +114,7 @@ inline void __const_udelay(unsigned long xloops)
        int d0;
 
        xloops *= 4;
-       __asm__("mull %0"
+       __asm__("mull %%edx"
                :"=d" (xloops), "=&a" (d0)
                :"1" (xloops), "0"
                (cpu_data(raw_smp_processor_id()).loops_per_jiffy * (HZ/4)));
index d0326d07c845bb9cfe806ae5b74a4ed14058e427..ff3dfecdb6f9c49589155771c02b8359a08ae3ec 100644 (file)
@@ -103,9 +103,16 @@ EXPORT_SYMBOL(__delay);
 
 inline void __const_udelay(unsigned long xloops)
 {
-       __delay(((xloops * HZ *
-               cpu_data(raw_smp_processor_id()).loops_per_jiffy) >> 32) + 1);
+       int d0;
+       xloops *= 4;
+       __asm__("mull %%edx"
+               :"=d" (xloops), "=&a" (d0)
+               :"1" (xloops), "0"
+               (cpu_data(raw_smp_processor_id()).loops_per_jiffy * (HZ/4)));
+
+       __delay(++xloops);
 }
+
 EXPORT_SYMBOL(__const_udelay);
 
 void __udelay(unsigned long usecs)