if (NumBits > 1) return NumBits;
}
- // FIXME: Should use computemaskedbits to look at the top bits.
- return 1;
+ // Finally, if we can prove that the top bits of the result are 0's or 1's,
+ // use this information.
+ uint64_t KnownZero, KnownOne;
+ uint64_t Mask = MVT::getIntVTBitMask(VT);
+ ComputeMaskedBits(Op, Mask, KnownZero, KnownOne, Depth);
+
+ uint64_t SignBit = MVT::getIntVTSignBit(VT);
+ if (KnownZero & SignBit) { // SignBit is 0
+ Mask = KnownZero;
+ } else if (KnownOne & SignBit) { // SignBit is 1;
+ Mask = KnownOne;
+ } else {
+ // Nothing known.
+ return 1;
+ }
+
+ // Okay, we know that the sign bit in Mask is set. Use CLZ to determine
+ // the number of identical bits in the top of the input value.
+ Mask ^= ~0ULL;
+ Mask <<= 64-VTBits;
+ // Return # leading zeros. We use 'min' here in case Val was zero before
+ // shifting. We don't want to return '64' as for an i32 "0".
+ return std::min(VTBits, CountLeadingZeros_64(Mask));
}