There is no need to mark the lower interrupts as reserved in order to
exclude them from dynamic allocation.
Provide arch_dynirq_lower_bound() to exclude the lower space.
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Reviewed-by: Grant Likely <grant.likely@linaro.org>
Cc: Tony Luck <tony.luck@intel.com>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Martin Schwidefsky <schwidefsky@de.ibm.com>
Cc: Heiko Carstens <heiko.carstens@de.ibm.com>
Cc: linux390@de.ibm.com
Link: http://lkml.kernel.org/r/20140507154339.811205235@linutronix.de
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
void __init init_IRQ(void)
{
- irq_reserve_irqs(0, THIN_INTERRUPT);
init_cio_interrupts();
init_airq_interrupts();
init_ext_interrupts();
return 0;
}
+unsigned int arch_dynirq_lower_bound(unsigned int from)
+{
+ return from < THIN_INTERRUPT ? THIN_INTERRUPT : from;
+}
+
/*
* Switch to the asynchronous interrupt stack for softirq execution.
*/