From: Yedidya Feldblum Date: Fri, 3 Mar 2017 05:32:09 +0000 (-0800) Subject: Tweak size handling in Endian X-Git-Tag: v2017.03.06.00~4 X-Git-Url: http://demsky.eecs.uci.edu/git/?a=commitdiff_plain;h=97377ac82a909b7d81537f5968381ea6af367a94;p=folly.git Tweak size handling in Endian Summary: [Folly] Tweak size handling in `Endian`. Either multiply by 8 in one place, or divide by 8 in another place. Go with the latter, because `sizeof` in C++ emits byte sizes, not bit sizes. Reviewed By: simpkins Differential Revision: D4645020 fbshipit-source-id: cb78600ba4c20bebc66aed506d4b5d6c378fc998 --- diff --git a/folly/Bits.h b/folly/Bits.h index 6c3c30ec..b818655e 100644 --- a/folly/Bits.h +++ b/folly/Bits.h @@ -241,7 +241,7 @@ struct uint_types_by_size; return fn(v); \ } \ template <> \ - struct uint_types_by_size { \ + struct uint_types_by_size { \ using type = uint##sz##_t; \ }; @@ -268,7 +268,7 @@ struct EndianInt { // we implement this with memcpy because that is defined behavior in C++ // we rely on compilers to optimize away the memcpy calls constexpr auto s = sizeof(T); - using B = typename uint_types_by_size<8 * s>::type; + using B = typename uint_types_by_size::type; B b; std::memcpy(&b, &x, s); b = byteswap_gen(b);